A: DBMS: Normalization to 2NF: 25

1NF

As there are non-atomic values in the column Contact_no, the table is violating 1NF. To make it conform to 1NF, let's decompose the table into R1 and R2.

In R1, we will place S_ID and Contact_no. The Primary Key here will be Composite Key(S_ID, Contact_no).

R1

S_ID Contact_no
S01 9841
S01 3762
S02 5532
S03 5361
S03 9857
S04 2734
S05 5736

 

In R2, we will have the remaining columns(other than Contact_no).

R2

S_ID S_name Address C_ID C_name
S01 Ram Birgunj C01 Database
S01 Ram Birgunj C02 E-Commerce
S02 Sita Kohalpur C03 MIS
S03 Krishna Bhojpur C01 Database
S04 Radha Damak C03 E-Commerce
S05 Rawan Dolpa C03 MIS
S03 Krishna Bhojpur C03 MIS

After eliminating the non-atomic values, the tables R1 and R2 conform to 1NF.

 

2NF

Here we will check if there are any partial dependencies.

In R1, there are no non-prime attributes. Thus, table R1 is already in 2NF.

In R2, we have considered the Composite Primary Key(S_ID, C_ID) and these are the partial functional dependencies:

{S_ID, C_ID} S_name

is a partial dependency because S_name can be derived from S_ID.

{S_ID, C_ID} S_name

is a partial dependency because Address can be derived from S_ID. 

{S_ID, C_ID} C_name

is a partial dependency because C_name can be derived from C_ID.

To eliminate these partial dependencies, we will decompose R2 into R3 and R4.

R3

S_ID S_name Address
S01 Ram Birgunj
S02 Sita Kohalpur
S03 Krishna Bhojpur
S04 Radha Damak
S05 Rawan Dolpa

 

R4

C_ID C_name
C01 Database
C02 E-Commerce
C03 MIS

As we have eliminated the partial dependencies, the tables R3 and R4 conform to 2NF. Thus the final tables R1, R3 and R4 are in 2NF.